The thicknesses of 13 randomly selected linoleum tiles were found to have a standard deviation of 4.76. Construct the 90% confidence interval for the population standard deviation of the thicknesses of all linoleum tiles in this factory. Round your answers to two decimal places.
Solution :
Given that,
s = 4.76
s2 = 22.6576
2L = 2/2,df = 21.026
2R = 21 - /2,df = 5.226
The 90% confidence interval for is,
(n - 1)s2 / 2/2 < < (n - 1)s2 / 21 - /2
12 * 22.6576 / 21.026 < < 12 * 22.6576 / 5.226
3.60 < < 7.21
(3.60 , 7.21)
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