Question

80% 90% 95% 98% 99% Mean 70611.96 70611.96 70611.96 70611.96 70611.96 Z score 1.28 1.64 1.96...

80% 90% 95% 98% 99%
Mean 70611.96 70611.96 70611.96 70611.96 70611.96
Z score 1.28 1.64 1.96 2.33 2.58
Standard Error 1516.38 1516.38 1516.38 1516.38 1516.38
Margin of Error 1943.32 2494.22 2972.05 3527.63 3905.93
Lower CI 68668.64 68117.74 67639.91 67084.34 66706.03
Upper CI 72555.28 73106.18 73584.01 74139.59 74517.90

What trend do you see takes place to the confidence interval as the confidence level rises? Explain mathematically why that takes place.

Homework Answers

Answer #1

Using the given data, we can see that the z score and margin of error are changing or we can say increasing for each confidence interval from 80% to 99% and this resulted in wider confidence interval width moving from 80% to 99%.

We know that the margin of error = z*(standard error)

so, it is clear that as z critical value increases with confidence level, the margin of error is also increasing.

Confidence interval width for 80% = upper limit - lower limit

= 72555.28 - 68668.64

= 3886.64

and

confidence interval width for 90% = upper limit - lower limit

= 73106.18-68117.74

= 4988.44

similarly, the confidence interval width for 99% = upper limit - lower limit

= 74517.90- 66706.03

= 7811.87

therefore, we can say that the trend is showing increase in width with increase in confidence level

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Sample mean is always: The lower endpoint of the 99% confidence interval. The middle of the...
Sample mean is always: The lower endpoint of the 99% confidence interval. The middle of the confidence 99% interval. The upper endpoint of the 99% confidence interval. The average monthly electricity consumption in a random sample of 100 households in February 2016 in North Kingstown was 637 kilowatt hours (kWh) with sample standard deviation s=45kwh. A 95% confidence interval for the true electricity consumption in North Kingstown is 637 ± 1.95 * 45/10 637 ± 1.96 * 45 637 ±...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the point estimate. Assume the data come from a normally distributed population. 13.3 11.6 11.9 12.2 12.5 11.4 12.0 11.7 11.8 13.3 (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) 90% confidence interval: enter the lower limit of the 90% confidence interval  ≤ μ ≤ enter the upper limit of the 90% confidence interval 95% confidence interval: enter the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the point estimate. Assume the data come from a normally distributed population. 13.7 11.6 11.9 13.0 12.5 11.4 12.0 11.7 11.8 13.7 Appendix A Statistical Tables (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) 90% confidence interval: enter the lower limit of the 90% confidence interval ≤ μ ≤ enter the upper limit of the 90% confidence interval...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the point estimate. Assume the data come from a normally distributed population. 13.1 11.6 11.9 12.0 12.5 11.4 12.0 11.7 11.8 13.1 Appendix A Statistical Tables (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) 90% confidence interval: enter the lower limit of the 90% confidence interval ≤ μ ≤ enter the upper limit of the 90% confidence interval...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the...
Construct 90%, 95%, and 99% confidence intervals to estimate μ from the following data. State the point estimate. Assume the data come from a normally distributed population. 12.0 11.6 11.9 12.9 12.5 11.4 12.0 11.7 11.8 12.0 Appendix A Statistical Tables (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) 90% confidence interval: enter the lower limit of the 90% confidence interval ≤ μ ≤ enter the upper limit of the 90% confidence interval...
A researcher computed 90%, 95%, 98% and 99% confidence intervals for a population mean. However, he...
A researcher computed 90%, 95%, 98% and 99% confidence intervals for a population mean. However, he forgot to record which interval was which, and he cannot find the sample data to allow him to recreate the intervals from scratch. He now needs only the 99% confidence interval. Which one is it?        a-(37.9, 42.1)         b-(38.4, 41.6)         c-(38.1, 41.9)         d-(38.7, 41.3)
In a small town, income level of households is an area of investigation. A researcher takes...
In a small town, income level of households is an area of investigation. A researcher takes a small sample. The following is the results: Sample size is 100. ?̅= 70 thousand. s= 5 thousand. Conf. Level Alpha Z 90% 10% 1.64 95% 5% 1.96 99% 1% 2.58 a) Construct a 95% confidence interval estimate for the population mean income level in this area.
A magazine company is planning to survey customers to determine the proportion who will renew their...
A magazine company is planning to survey customers to determine the proportion who will renew their subscription for the coming year. The magazine wants to estimate the population proportion with 90​% confidence and a margin of error equal to plus or minus±0.07 Confidence Level Critical Value ​80% z=1.28 ​90% z=1.645 ​95% z=1.96 ​99% z=2.575 What sample size is​ required?
A medical statistician wants to estimate the average weight loss of those who have been on...
A medical statistician wants to estimate the average weight loss of those who have been on a new diet plan for 2 weeks. From a random sample of 100 participants in the diet plan, a mean weight change of -2.5 pounds and a standard deviation of 10 pounds are observed. In order to claim that the diet plan is effective, the whole part of the confidence interval for the mean weight change has to be below zero. In other words,...
1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample...
1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample mean is 10 with the sample size of 100. Population standard deviation is known to be 5. 2. Suppose that sample size changes to 144 and 225. Develop three confidence intervals again. What happens to the margin of error when sample size increases? 3. A simple random sample of 400 individuals provides 100 yes responses. Compute the 90%, 95%, and 99% confidence interval for...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT