If n = 100 and X = 80, construct a 95% confidence interval for the population proportion, p. Give your answers to three decimals < p
We have given,
x=80
n=100
Estimate for sample proportion=\hat{p}= 0.8
Level of significance is =1-0.95=0.05
Z critical value(using Z table)=1.96
Confidence interval formula is
=(0.722,0.878)
Therefore, a 95% confidence interval for the population proportion,
p is
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