Question

If n = 100 and X = 80, construct a 95% confidence interval for the population proportion, p. Give your answers to three decimals < p

Answer #1

We have given,

x=80

n=100

Estimate for sample proportion=\hat{p}= 0.8

Level of significance is =1-0.95=0.05

Z critical value(using Z table)=1.96

Confidence interval formula is

=(0.722,0.878)

Therefore, a 95% confidence interval for the population proportion,
p is

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