Previous experience shows the variance of a given process to be 14. Researchers are testing to determine whether this value has changed. They gather the following dozen measurements of the process. Use these data and α=0.05 to test the null hypothesis about the variance. Assume the measurements are normally distributed.
52 |
44 |
51 |
58 |
48 |
49 |
38 |
49 |
50 |
42 |
55 |
51 |
H0: the variance of the given process is 14. i.e
H1: this value has changed. That is, the variance of the given process is not 14 i.e.
Given, the sample size n = 12
Sample variance
Now,
Therefore,
So, s2= 29045/12 - 45.41672 = 357.7400
Test statistic is
Level of significance
The critical value is for n - 1 = 12 - 1 = 11 degrees of freedom is 19.68.
The value of the test statistic is 306.63 > 19.68
So, the null hypothesis H0 is rejected at
Hence, we conclude that the variance has changed, i.e. the variance of the given process is not 14.
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