A data set includes data from student evaluations of courses. The summary statistics are n equals=92, x equals=4.09, s equals=0.62. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative hypotheses?
Determine the test statistic.
(Round to two decimal places as needed.)
Determine the P-value.
(Round to three decimal places as needed.)
State the final conclusion that addresses the original claim.
? H0. There is ? evidence to conclude that the original claim that the mean of the population of student course evaluations is equal to 4.25 ? correct.
The null and alternative hypothesis are
H0: = 4.25
Ha: 4.25
Test statistics
t = - / ( S / sqrt(n) )
= 4.09 - 4.25 / (0.62 / sqrt(92) )
= -2.48
From T table,
With test statistics -2.48 and df of 91,
p-value (Two tailed) = 0.015
Since p-value < 0.05 level, we have sufficient evidence to reject H0.
We conclude at 0.05 level that we have sufficient evidence to support the claim.
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