Question

A bacteria has a doubling period of 8 days. If there are 3400 bacteria present now, how many will there be in 32 days? First we must find the daily growth rate (Round this to four decimal places).

The growth rate is _________ ?

Then we use this rate to answer the question.
There will be _____________ bacteria

Answer 1

Answer:

Formula is

n = k*2^(t/d)

where n is the number of bacteria after t minutes, k is the number of bacteria at time zero, d is the time in minutes that it takes to double, and t is the time in minutes at which we are counting the bacteria.

Now, k = 3400, d = 8 days, t = 32 days

Therefore,

n = 3400*2^32/8)

= 3400*2^(4)

3400*16 = 54400

Hence the number of bacteria after 25 days will be approx. 54400

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