Question

**Among coffee drinkers, men drink a mean of 3.2 cups per
day with a standard deviation of 0.8 cups. There is an outlier in
this data making it positively skewed.**

**If a sample of 36 men is selected, what is the
probability that the mean number of cups per day is less than
3?**

Answer #1

Solution :

Given that,

mean = = 3.2

standard deviation = = 0.8

n = 36

= 0.8

= / n = 0.8 / 36=0.13333

P( < 3) = P[( - ) / < (3-3.2) / 0.13333]

= P(z <-1.50 )

Using z table

= 0.0668

probability= 0.0668

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