Question

A genetic experiment involving peas yielded one sample of offspring consisting of 437 green peas and 121 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Answer #1

Null and alternative hypotheses

Ho : p = 0.24

Ha : p = 0.24

Test statistic Z

Z = ( p^ - p)/sqrt[ p*q/n]

Where p^ = X/n = number of yellow offspring peas/total number of offspring peas

p^ = 121/558 = 0.22

Z = (0.22 - 0.24)/sqrt[0.24*0.76/558]

Z = -1.11 this is test statistic value

p-value for Z = -1.11 and two tailed test

p-value = 2* P( Z < -1.11)

p-value = 0.2670

Here p-value = 0.2670 > 0.01

Decision : we fail to reject the null hypothesis Ho

Conclusion : There is sufficient evidence to support the claim that

under the same circumstances, 24% of offspring peas will be yellow

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the null hypothesis, and final conclusion that addresses the
original claim. Use the P-value method and the normal distribution
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P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.

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offspring consisting of 404 green peas and 134 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 24% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
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conclusion that addresses the original claim. Use the P-value
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HW8#11
A genetic experiment involving peas yielded one sample of
offspring consisting of 448 green peas and 174 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
A. what...

A genetic experiment involving peas yielded one sample of
offspring consisting of 448 green peas and 140 yellow peas. Use a
0.05 significance level to test the claim that under the same
circumstances, 26% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
What is the...

A genetic experiment
involving peas yielded one sample of offspring consisting of 405
green peas and 156
yellow peas. Use a
0.05 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution
What is the...

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