Question

Software analysis of the salaries of a random sample of 251 teachers in a particular state...

Software analysis of the salaries of a random sample of 251 teachers in a particular state produced the confidence interval shown below. Determine if the following conclusions are correct. If​ not, state what is wrong with the conclusion. Complete parts a through e below. ​t-interval for mu ​: with 99 ​% ​confidence, 43623 less thanmu​(TchPay)less than45465 ​

a) If many random samples of 251 teachers from this state were​ taken, about 99 out of 100 of them would produce this confidence interval. Choose the correct answer below.

A. This conclusion is​ correct, assuming all assumptions and conditions are met.

B. This conclusion is incorrect. About 99 out of 100 intervals will produce a confidence interval that overlaps with this interval.

C. This conclusion is incorrect. About 99 out of 100 intervals based on samples of any size would produce this confidence interval.

D. This conclusion is incorrect. About 99 out of 100 intervals will contain the true mean​ salary, but different samples of 251 teachers will produce different confidence intervals. ​

b) If many random samples of teachers from this state were​ taken, about 99 out of 100 of them would produce a confidence interval that contained the mean salary of all teachers from this state. Choose the correct answer below.

A. This conclusion is​ correct, assuming all assumptions and conditions are met.

B. This conclusion is incorrect. All 100 of the intervals will contain the true mean​ salary, but different samples of 251 teachers will produce different confidence intervals.

C. This conclusion is incorrect. About 99 out of 100 teachers surveyed will earn a salary within the interval.

D. This conclusion is incorrect. About 99 out of 100 intervals will produce a confidence interval that overlaps with this interval. ​

c) About 99 out of 100 teachers from this state earn between ​$43 comma 623 and ​$45 comma 465 . Choose the correct answer below.

A. This conclusion is incorrect. The interval is for the population mean​ salary, not the salary for individual teachers.

B. This conclusion is​ correct, assuming all assumptions and conditions are met.

C. This conclusion is incorrect. The interval means that a newly hired teacher in this state has a 99 ​% chance of earning between ​$43 comma 623 and ​$45 comma 465 .

D. This conclusion is incorrect. The interval is for the sample mean​ salary, not the salary for individual teachers. ​

d) About 99 out of 100 of the teachers surveyed earn between ​$43 comma 623 and ​$45 comma 465 . Choose the correct answer below.

A. This conclusion is incorrect. The interval is for the population mean​ salary, not the salary for individual teachers.

B. This conclusion is​ correct, assuming all assumptions and conditions are met.

C. This conclusion is incorrect. The interval is for the sample mean​ salary, not the salary for individual teachers.

D. This conclusion is incorrect. The interval means that a newly hired teacher in this state has a 99 ​% chance to earn between ​$43 comma 623 and ​$45 comma 465 . ​

e) We are 99 ​% confident that the average teacher salary in the entire country is between ​$43 comma 623 and ​$45 comma 465 . Choose the correct answer below.

A. This conclusion is incorrect. The confidence interval addresses only the salaries of teachers in this state.

B. This conclusion is​ correct, assuming all assumptions and conditions are met.

C. This conclusion is incorrect. The confidence interval addresses only the salaries of teachers surveyed in the sample of 251 .

D. This conclusion is incorrect. A larger sample from the state is needed in order to construct a confidence interval estimate for the salaries of teachers across the entire country.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of 75 New York public school teachers was surveyed about their salaries. Their mean...
A sample of 75 New York public school teachers was surveyed about their salaries. Their mean salary was $65467 with a standard deviation of $5130. a. Use the Confidence Interval Calculator and a 90% confidence level to estimate the population mean salary. $65467 +/- $ b. Use a 95% confidence level to estimate the population mean salary. $65467 +/- $ c. Use a 99% confidence level to estimate the population mean salary. $65467 +/- $
Salary data from two random samples of high school teachers are shown to the right. Also...
Salary data from two random samples of high school teachers are shown to the right. Also shown are the population standard deviations. Construct a 90% confidence interval to estimate the difference in the average salaries of the high school teachers in these two states. b. Based on the results in part? a, can you conclude that a difference exists in the average? salaries? state A state B sample mean 52,236 57,231 sample size 43 49 population standard deviation 6207 6671...
A random sample of the closing stock prices in dollars for a company in a recent...
A random sample of the closing stock prices in dollars for a company in a recent year is listed below. Assume that sigma is ​$2.29. Construct the 90​% and 99​% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. 18.16 17.37 20.79 21.54 16.89 19.22 22.91 18.71 15.42 15.21 20.67 20.85 18.53 22.85 18.47 17.13 The​ 90% confidence interval is left parenthesis $ nothing comma $ nothing right parenthesis . ​(Round to...
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is...
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bottle is determined. Let μ denote the average alcohol content for the population of all bottles of the brand under study. Suppose that the resulting 95% confidence interval is (7.6, 9.2). (a) Would a 90% confidence interval calculated from this same sample have been narrower or wider than the given interval? Explain your reasoning. The 90% would...
These next few questions ask about confidence intervals. a) Bruce Wayne studies. A random sample of...
These next few questions ask about confidence intervals. a) Bruce Wayne studies. A random sample of data on a categorical variable and calculates a 95% confidence interval for the population proportion to be (0.546, 0.674). Determine what the sample proportion must have been, and explain why. b) Suppose Clark and Lois plan to collect separate random samples, with Clark using a sample size of 500 and Lois using a sample size of 1500. Brad plans to construct a 99% confidence...
The following data represent the pH of rain for a random sample of 12 rain dates....
The following data represent the pH of rain for a random sample of 12 rain dates. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts​ (a) through​ (d) below. DATA: 5.20, 5.72, 4.38, 4.80, 5.02, 5.16, 4.74, 5.19, 5.34, 4.76, 4.56, 4.68 ​(a) Determine a point estimate for the population mean. A point estimate for the population mean is _______???? (round to 2 decimal...
In a random sample of 35 Penn State Shenango students, 17 were attending full-time. In a...
In a random sample of 35 Penn State Shenango students, 17 were attending full-time. In a random sample of 40 World Campus students, 13 were attending full-time. Use Minitab Express to construct a 95% confidence interval to estimate the difference between the proportions of all Penn State Shenango and all Penn State World Campus students who are attending full-time. If assumptions are met, use the normal approximation method. Remember to copy + paste all relevant Minitab Express output. Clearly identify...
Close Friends: The 2004 General Social Survey (GSS) interviewed a random sample of adult Americans. For...
Close Friends: The 2004 General Social Survey (GSS) interviewed a random sample of adult Americans. For one question the interviewer asked: “From time to time, most people discuss important matters with other people. Looking back over the last six months – who are the people with whom you discussed matters important to you? Just tell me their first names or initials.” The interviewer then recorded how many names or initials the respondent mentioned. Results are tallied in the following table:...
A company that produces cell phones claims its standard phone battery lasts longer on average than...
A company that produces cell phones claims its standard phone battery lasts longer on average than other batteries in the market. To support this​ claim, the company publishes an ad reporting the results of a recent experiment showing that under normal​ usage, their batteries last at least 35 hours. To investigate this​ claim, a consumer advocacy group asked the company for the raw​ data, which are shown to the right. Find a 95 ​% confidence interval and state your conclusion....
The Federal Election Commission collects information about campaign contributions and disbursements for candidates and political committees...
The Federal Election Commission collects information about campaign contributions and disbursements for candidates and political committees each election cycle. During the 2012 campaign season, there were 1,619 candidates for the House of Representatives across the United States who received contributions from individuals. The table below shows the total receipts from individuals for a random selection of 40 House candidates rounded to the nearest $100. $3,600 $1,243,900 $10,900 $385,200 $581,500 $7,400 $2,900 $400 $3,714,500 $632,500 $391,000 $467,400 $56,800 $5,800 $405,200 $733,200...