Question

A researcher predicts that scores in treatment A will be higher than scores in treatment B. If the mean for the 8 participants in treatment A is 4 points higher than the mean for the 8 participants in treatment B and the data produce t = 1.652, what decision should be made? Show steps.

a.	With a = .05, fail to reject H0 for either a one-tailed or a two-tailed test
b.	With a = .05, reject H0 for either a one-tailed or a two-tailed test
c.	With a = .05, reject H0 for a one-tailed test but fail to reject for a two-tailed test
d.	With a = .05, reject H0 for a two-tailed test but fail to reject for a one-tailed test

---- steps:

Answer 1

t stat = 1.652

df = 8 - 1 = 7

t critical for df = 7 and level of significance = 0.05

t-value (right-tail): 1.895 : As the t stat does not fall in rejection area, we fail to reject the Ho.

t- value (left tailed) : - 1.895 : As the t stat does not fall in rejection area, we fail to reject the Ho.

t-value (two-tailed) : +/- 2.36462425:  As the t stat does not fall in rejection area, we fail to reject the Ho.

ANS: Option a) With a = .05, fail to reject H0 for either a one-tailed or a two-tailed test