Question

Thirty-eight percent of all Americans drink bottled water more
than once a week (Natural resources Defense Council, December 4,
2015). Suppose you have been hired by the Natural Resources Defence
Council to investigate bottled water consumption in St. Paul. You
plan to select a sample of St. Paulites to estimate the proportion
who drink bottled water more than once a week. Assume the
population proportion of St. Paulites who drink bottled water more
than once a week is , the same as the overall proportion of
Americans who drink bottled water more than once a week. Use
*z*-table.

**a.** Suppose you select a sample of 540
St.Paulites. Show the sampling distribution of p (to 4
decimals).

**b.** Based upon a sample of 540 St. Paulites,
what is the probability that the sample proportion will be within
0.05 of the population proportion (to 4 decimals).

probability

**c.** Suppose you select a sample of 240
St.Paulites. Show the sampling distribution of p (to 4
decimals).

**d.** Based upon a smaller sample of only 240 St.
Paulites, what is the probability that the sample proportion will
be within .05 of the population proportion (to 4 decimals).

probability

**e.** As measured by the increase in probability,
how much do you gain in precision by taking the larger sample in
parts (**a**) and (**b**) rather than the
smaller sample in parts (**c**) and
(**d**)?

Reduced by _______ ?

Answer #1

P values can be taken from Excel ,

=Norm.s.dist(z, cumulative)

= Norm.s.dist(-2.39,1) = 0.9916

=Norm.s.dist(2.39,1) =0.0084

Thirty-seven percent of all Americans drink bottled water more
than once a week (Natural resources Defense Council, December 4,
2015). Suppose you have been hired by the Natural Resources Defence
Council to investigate bottled water consumption in St. Paul. You
plan to select a sample of St. Paulites to estimate the proportion
who drink bottled water more than once a week. Assume the
popluation proportion of St. Paulites who drink bottled water more
than once a week is 0.37, the...

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The National Resource Defense Council concludes, “there is no
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Let’s suppose that the city council members of Corvallis are
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The Food Marketing Institute shows
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What is the probability that the sample proportion will be
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The Food Marketing Institute shows that 15% of households spend
more than $100 per week on groceries. Assume the population
proportion is p = 0.15 and a sample of 700 households will
be selected from the population. Use z-table.
Calculate (), the standard error of the proportion of
households spending more than $100 per week on groceries (to 4
decimals).
What is the probability that the sample proportion will be
within +/- 0.02 of the population proportion (to 4...

The Food Marketing Institute shows that 15% of households spend
more than $100 per week on groceries. Assume the population
proportion is p = 0.15 and a sample of 600 households will be
selected from the population. Use z-table.
Calculate (), the standard error of the proportion of households
spending more than $100 per week on groceries (to 4 decimals).
What is the probability that the sample proportion will be
within +/- 0.02 of the population proportion (to 4 decimals)?...

The Food Marketing Institute shows that 16% of households spend
more than $100 per week on groceries. Assume the population
proportion is p = 0.16 and a sample of 900 households will be
selected from the population. Use z-table. Calculate (), the
standard error of the proportion of households spending more than
$100 per week on groceries (to 4 decimals). 0.0130 What is the
probability that the sample proportion will be within +/- 0.03 of
the population proportion (to 4...

The Food Marketing Institute shows that 15% of households spend
more than $100 per week on groceries. Assume the population
proportion is p = 0.15 and a sample of 800 households will
be selected from the population. Use z-table.
What is the probability that the sample proportion will be
within +/- 0.02 of the population proportion (to 4 decimals)?
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