A physician would like to test the hypothesis that the mean body temperature (in degrees Fahrenheit) of adults is not 98.6. For the test, they will assume the temperatures follow a normal distribution with a standard deviation of 0.9. The physician selects a random sample of 10 adults and finds that they have a mean body temperature of 98.2.
A) calculate the test statistic for testing the physician's hypothesis.
B) Determine the p- value for the test.
Solution :
= 98.6
= 98.2
s = 0.9
n = 10
This is the two tailed test .
The null and alternative hypothesis is
H0 : = 98.6
Ha : 98.6
Test statistic = t
= ( - ) / s / n
= (98.2 -98.6) / 0.9/ 10
= -1.405
P (Z < -1.405 ) =0.1936
P-value = 0.1936
= 0.05
0.1936 > 0.05
Do not reject the null hypothesis .
There is insufficient evidence to suggest that
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