Poisson distribution Exercise
Q3. During the 30-year period 1959-1988, a total of 138 tornadoes were reported in New York State. Let X denote the number of tornadoes reported per year in New York State and assume that X follows a Poisson distribution. Estimate the probability that, during a given year, New York State reports:
a. No tornadoes
b. At most three tornadoes
c. More than two but not more than five tornadoes
d. At least six tornadoes
Express probabilities to six decimal places
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Ans:
Average number of tornadoes per year=138/30=4.6
Use Poisson distribution:
P(x=k)=exp(-4.6)*(4.6^k/k!)
a)
P(x=0)=exp(-4.6)*(4.6^0/0!)=0.010052
b)
P(at most 3)=P(x<=3)
=exp(-4.6)*(4.6^0/0!+4.6^1/1!+4.6^2/2!+4.6^3/3!)
=0.325706
c)
P(2<x<=5)=P(x=3)+P(x=4)+P(x=5)
=exp(-4.6)*(4.6^3/3!+4.6^4/4!+4.6^5/5!)
=0.163068+0.187528+0.172526
=0.523121
d)
P(at least 6)=P(x>=6)=1-P(x<=5)
=1-exp(-4.6)*(4.6^0/0!+4.6^1/1!+4.6^2/2!+4.6^3/3!+4.6^4/4!+4.6^5/5!)
=0.314240
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