A small manufacturing company has 340 employees (excluding top management) classified as supervisors, professional staff, and blue collar workers. It is known that there are 20 supervisors, and 70% of all employees are blue collar workers. Two percent of supervisors, 40% of professional staff, and 74% of blue collar workers are union members. Construct a contingency table given the above data.
a- What percentage of workers are union members?
b- If a random union member employee is selected, what is the probability that he/she is a professional staff?
c- If a random worker is selected, what is the probability that we pick a blue collar union member worker?
d- If a random worker is selected, find the probability of picking a professional staff or non-union employee?
e- Are the classification of workers and their union affiliation independent? Show with calculation.
from given data:
supervisors | professional staff | blue collar | total | |
union\ | 0.4 | 32.8 | 176.12 | 209.32 |
not union | 19.6 | 49.2 | 61.88 | 130.68 |
total | 20 | 82 | 238 | 340 |
a)
percentage of workers are union members =(209.32/340)*100=61.56
b) probability that he/she is a professional staff =82/340=0.2411
c) probability that we pick a blue collar union member worker =176.12/340=0.5180
d)probability of picking a professional staff or non-union employee =(82+19.6+61.88)/340=0.4808
e)
here P(blue coller)*P(union member)=(238/340)*(209.32)/340)=0.4309 whcihn is not equal to P(blue collar and union member from part C. hence not independent
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