The library states that 90% of books taken out of the library are returned before their due date. In a sample of 61 books, what is the probability that less than 80% were returned before their due date?
a) -2.60
b) 0.0047
c) 0.9953
d 0.1000
Solution
Given that,
p = 0.90
1 - p = 1-0.90=0.10
n = 61
= p =0.90
= [p ( 1 - p ) / n] = [(0.90*0.10) / 61 ] = 0.03841
P( <0.80 ) =
= P[( - ) / < (0.80-0.90) /0.03841 ]
= P(z <-2.60 )
Using z table,
probability =0.0047
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