Find the margin of error for 1−α = 0.98, σ = 1.05, and n = 160?
a-0.193
b- 0.171
c-0.015
d- 0.013
Solution :
Given that,
Population standard deviation =
= 1.05
Sample size = n =160
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
Z/2 = Z0.01 = 2.326 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 2.326 * ( 1.05/ 160
)
=0.193
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