6. The value of the residuals for a linear regression model with six observations is given in the table below.
Observation number 1, 2, 3, 4, 5, 6
Residual (ei) 1.1, 4.2, -0.5, -3.7, 2.3, -1.9
(a) Compute the value of the residual variance for this sample.
(b) Compute the value of the residual standard error for this sample.
(c) Explain why the residual variance is useful in hypothesis tests for the slope and the intercept.
Residuals( e) | e^2 | ||
1.1 | 1.21 | ||
4.2 | 17.64 | ||
-0.5 | 0.25 | ||
-3.7 | 13.69 | ||
2.3 | 5.29 | ||
-1.9 | 3.61 | ||
Total | SSE = | 41.69 | SUM(e^2) |
n = | 6 | ||
Se^2 = | MSE = | 4.948333 | SSE/n-2 |
Se = | 2.224485 | SQRT(MSE) |
a)
the value of the residual variance for this sample = Se^2 = 4.948
b)
the value of the residual standard error for this sample = Se = 2.224
c)
t stat for intercept and slope
t = bi/Sbi
Sb0 = Se * (1/n+Xbar^2/SSxx)^2
Sb1 = Se/SQRT(SSxx)
Standard error of slope or intercept is directly proportional to the standard error of regression
Standard error of regression is used to find slope and intercept standard errors
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