You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures:
18.2 |
15.9 |
25.1 |
8.4 |
24 |
18.9 |
21.9 |
18.3 |
18.1 |
Find the 90% confidence interval. Enter your answer as an
open-interval (i.e., parentheses)
accurate to two decimal places (because the sample data are
reported accurate to one decimal place)
We have given that,
Sample mean =18.76
Sample standard deviation =4.9245
Sample size =9
Level of significance=1-0.90=0.1
Degree of freedom =8
t critical value is (by using t table)=
1.86
Confidence interval formula is
=(15.71,21.81)
Lower confidence limit= 15.71
Upper confidence limit= 21.81
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