Reading proficiency: An educator wants to construct a 99%
confidence interval for the proportion
of elementary school children in Colorado who are proficient in
reading.
(b) Estimate the sample size needed if no estimate of P is available.
A sample of __ elementary school children is needed to obtain a
99% confidence interval
with a margin of error of 0.03.
Solution :
Given that,
= 0.5 ( assume 0.5)
1 - = 1 - 0.5 = 0.5
margin of error = E =0.03
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (2.576 / 0.03)2 * 0.5 * 0.5
=1843.27
Sample size = 1844
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