Question

The value in dollars of a certain stock at the end of the month approximately follows...

The value in dollars of a certain stock at the end of the month approximately follows a normal distribution with mean 11 and standard deviation 2.5. An investor will buy the stock at the end of the month if its price is no higher than $6. Use the 68-95-99.7 Rule to estimate the percentage of times that the investor would buy the stock.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose the scores on an IQ test approximately follow a normal distribution with mean 100 and...
Suppose the scores on an IQ test approximately follow a normal distribution with mean 100 and standard deviation 12. Use the 68-95-99.7 Rule to determine approximately what percentage of the population will score between 100 and 124.
3000 students take a college entrance exam. The scores on the exam have an approximately normal...
3000 students take a college entrance exam. The scores on the exam have an approximately normal distribution with mean mu equals53 points and standard deviation sigma equals10 points. Use the? 68-95-99.7 rule to complete the following. a. Estimate the percentage of students scoring 53 points or less . b. Estimate the percentage of students scoring 73 points or more .
The distribution of math test scores on a standardized test administered to Texas tenth-graders is approximately...
The distribution of math test scores on a standardized test administered to Texas tenth-graders is approximately Normal with a mean of 615 and a standard deviation of 46. Below what score do the worst 2.5% of the scores fall? (Hint: apply the 68-95-99.7 Rule.) Round your answer to the nearest integer.
According to the 68-95-99.7 Rule for normal distributions approximately _____% of all values are within 1...
According to the 68-95-99.7 Rule for normal distributions approximately _____% of all values are within 1 standard deviation of the mean
The times for the mile run of a large group of male college students are approximately...
The times for the mile run of a large group of male college students are approximately Normal with mean 7.1 minutes and standard deviation 0.79 minutes. Use the 68-95-99.7 rule to answer the following questions. (Start by making a sketch of the density curve you can use to mark areas on.) (a) What range of times covers the middle 99.7% of this distribution? (b) What percent of these men run a mile in more than 7.89 minutes?
(01.06 LC) The weight of laboratory grasshoppers follows a Normal distribution, with a mean of 90...
(01.06 LC) The weight of laboratory grasshoppers follows a Normal distribution, with a mean of 90 grams and a standard deviation of 2 grams. What percentage of the grasshoppers weigh between 86 grams and 94 grams? (3 points) 99.7% 95% 68% 47.5% 34%
The upper arm length of males over 20 years old in the United States is approximately...
The upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.1 cm and standard deviation 2.3 cm. Use the 68-95-99.7 rule to answer the following questions. (a) What range of lengths covers the middle 99.7% of this distribution? (b) What percent of men over 20 have upper arm lengths greater than 41.4 cm?
The distribution of young woman's height is normally distributed with a mean of 65 inches and...
The distribution of young woman's height is normally distributed with a mean of 65 inches and a standard deviation of 2.5 between what height do 95% of young women fall and what percentage of young women are shorter and 65 68-95-99.7 rule The IQ score of seven graders normally distributed with a mean of 111 standard deviation of 11 what percentage IQ score above 144 in a sample of 75 students in a rural school none had scored above 144...
The time needed for students complete a certain paper and pencil maze follows an approximately Normal...
The time needed for students complete a certain paper and pencil maze follows an approximately Normal distribution and has a mean of 70 seconds and a standard deviation of 15 seconds. a) If a student takes 100 seconds to complete the maze, what percentile would the student be? b) What percentage of students complete the maze between 50 and 60 seconds?
Not everyone pays the same price for the same model of a car. The figure illustrates...
Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $ 21,000 and the standard deviation is $2000. Use the 68-95-99.7 Rule to find what percentage of buyers paid between $ 19,000 and $ 21,000. is ? %
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT