If a random sample of 100 items is taken from a population in which the proportion of items having a desired attribute is p=0.30, what is the probability that the proportion of successes in the sample will be less than or equal to 0.33?
Solution
Given that,
p = 0.30
1 - p = 1 - 0.30 = 0.70
n = 100
= p = 0.30
= p ( 1 - p ) / n
= (0.30 * 0.70) / 100 = 0.0458
P( 0.33) =
= P(( - ) / < (0.33 - 0.30) / 0.0458)
= P(z < 0.655)
= 0.7438
Probability = 0.7438
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