60% of the studentsin a lecture are males. 100 students are selected randomly.
a.Find the standars error of the sample.
b.Find the probability of the sample proportion being greater than 0.70
Solution
Given that,
p = 0.60
1 - p = 1 - 0.60 = 0.40
n = 100
= p = 0.60
a) = [p( 1 - p ) / n] = [(0.60 * 0.40) / 100] = 0.0490
b) P( > 0.70) = 1 - P( < 0.70)
= 1 - P(( - ) / < (0.70 - 0.60) / 0.0490)
= 1 - P(z < 2.04)
Using z table
= 1 - 0.9793
= 0.0207
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