#11 Please show work: The data below represents the fields of specialization for a randomly selected sample of undergraduate students. We want to determine whether there is any dependency between the fields of specialization and the regions of the country.
Northeast |
Midwest |
South |
West |
Total |
|
Business |
54 |
65 |
28 |
93 |
240 |
Engineering |
15 |
24 |
8 |
33 |
80 |
Liberal Arts |
65 |
84 |
33 |
98 |
280 |
Fine Arts |
13 |
15 |
7 |
25 |
60 |
Health Sciences |
3 |
12 |
4 |
21 |
40 |
150 |
200 |
80 |
270 |
700 |
a. Determine the critical value of the chi-square χ2 for this test of independence.
b. Calculate the value of the test statistic.
c. What is the conclusion for this test? Let α= .05.
d.Let α= .05. Compute the test statistic for the goodness of fit test.
e. At the 5% level of significance using the p-value approach, test the hypotheses. What do you conclude about the distribution?
Observed | |||||
Northeast | midwest | south | west | total | |
Business | 54 | 65 | 28 | 93 | 240 |
Engg | 15 | 24 | 8 | 33 | 80 |
Liberal arts | 65 | 84 | 33 | 98 | 280 |
fine arts | 13 | 15 | 7 | 25 | 60 |
health science | 3 | 12 | 4 | 21 | 40 |
Total | 150 | 200 | 80 | 270 | 700 |
Expected value = sum(coli)*sum(rowi)/total
Expected | ||||
Northeast | midwest | south | west | |
Business | 51.429 | 68.571 | 27.429 | 92.571 |
Engg | 17.143 | 22.857 | 9.143 | 30.857 |
Liberal arts | 60.000 | 80.000 | 32.000 | 108.000 |
fine arts | 12.857 | 17.143 | 6.857 | 23.143 |
health science | 8.571 | 11.429 | 4.571 | 15.429 |
test statistic, chi-square = sum((Oi - Ei)^2/Ei) = 8.67
a)
Critical value = 21.03
b)
test statistic, chi-square = 8.67
c)
Fail to reject null hypothesis.
d)
Test statistic, chi-square = 8.67
e)
p-value = 0.73
Fail to reject H0
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