The proportion of drivers who use seat belts depends factors such as age (young people are more likely to go unbelted) and sex (women are more likely to use belts). It also depends on local law. In New York City, police can stop a driver who is not belted. In Boston at the time of the survey, police could cite a driver for not wearing a seat belt only if the driver had been stopped for some other violation. Here are data from observing random samples of female Hispanic drivers in these two cities.
City | Drivers | Belted |
---|---|---|
New York | 213 | 175 |
Boston | 115 | 73 |
Comparing local laws suggests the hypothesis that a smaller proportion of drivers wear seat belts in Boston than in New York. Do the data give good evidence that this is true for female Hispanic drivers? (Use α = 0.05. Round your test statistic to two decimal places and your P-value to four decimal places.)
H0: | pNY (= < > ≠) pB |
Ha: | pNY (< ≠ > =) pB |
z = | |
P-value = |
CHOOSE ONE OF THE FOUR SYMBOLS IN THE PARENTHESIS
Given that,
For New York : n1 = 213, x1 = 175 and
For Bostan : n2 = 115, x2 = 73 and
Pooled proportion is,
The null and alternative hypotheses are,
H0 : pNY = pB
Ha : pNY > pB
This hypothesis test is a right-tailed test.
Test statistic is,
=> Z = 3.76
p-value = P(Z > 3.76) = 1 - P(Z < 3.76) = 1 - 0.9999 = 0.0001
=> p-value = 0.0001
Since, p-value is less than 0.05 level of significance, we reject the null hypothesis (H0).
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