(a)
D = event that someone has taken drug.
P(D) = 0.02
C = event that someone is caught and disqualified
P( D C ) = 0.02 * 0.99 = 0.0198
P( D' C ) = 0.98 * 0.03 = 0.0294
P( D C' ) = 0.02 * 0.01 = 0.002
P( D' C' ) = 0.98 * 0.97 = 0.9506
(b)
P( randomly chosen cyclist will be steroid free and will still test for steroids )
= P( C D' ) =0.0294
(c)
P( randomly chosen cyclist will be disquilified due to positive reading )
= P( C D ) + P( C D')
= 0.0198 + 0.0294
= 0.0492
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