We have computer output for a SLR model with n=30.
Estimate |
Standard error |
|
(intercept) |
12.0 |
6.00 |
X |
8.0 |
0.90 |
95 % confidence interval for beta1 (b1)is -
( b1 - t * SEb1) , ( b1 + t * SEb1)
Where SEb1 is standard error of b1 = 0.90
t = 2.05. ( Given)
b1 = 8.0
95% confidence interval for beta1 -
( 8.0 - 2.05 * 0.90) , ( 8.0 + 2.05 * 0.90)
( 6.155 , 9.845 )
B) test statistic is = b1 / SEb1
t stat = 8.0/0.90
t stat = 8.8888
Pvalue = 0.0001
Alpha = 0.05
t critical value is 2.04
Decision - As pvalue less than alpha 0.05 so we Reject the null hypothesis.
Conclusion - as we reject H0 , Hence we say that there is significantly linear relationship between x and y variable.
Get Answers For Free
Most questions answered within 1 hours.