Question

1a. Given: mean difference between men and women = 2.2; standard error of mean difference = 0.8; n men = 61, n women = 61.

Test the following null hypothesis at a=.05

Ho: u men = u women

Ha: u men > u women

You need to compute the **t statistic**, look up
**t critical value** and **make
decision** including **likelihood of appropriate
error**. You **don't** have to compute the
**standard error of mean difference** because
**it's given**.

**1b. Compute the appropriate confidence interval for the
two-sample t-test of the previous question. Make sure you look at
the alternative hypothesis before computing this
interval.**

**Please upload into a Microsoft Word file and show work
for answers**

Answer #1

we have given mean difference between men and women() = 2.2;

standard error of mean difference(SE)= 0.8;

nm = 61, n w = 61.

Ho: u men = u women

Ha: u men > u women

a ) t = () / SE = 2.2/0.8 = 2.75

t at 0.05 with 120 df (one tailed ) = 1.657

since t calculated >1.657 so we reject Ho

b ) t at 0.05 with 120 df (two tailed ) = 1.98 ( for constructing Confidence interval)

95%CI = () +/- t*SE = 2.2 +/- 1.98*0.8 = 2.2+/-1.584= (0.616,3.784)

since confidence interval do not contain 0 so we reject Ho

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