Question

# 1a. Given: mean difference between men and women = 2.2; standard error of mean difference =...

1a. Given: mean difference between men and women = 2.2; standard error of mean difference = 0.8; n men = 61, n women = 61.

Test the following null hypothesis at a=.05

Ho: u men = u women

Ha: u men > u women

You need to compute the t statistic, look up t critical value and make decision including likelihood of appropriate error. You don't have to compute the standard error of mean difference because it's given.

1b. Compute the appropriate confidence interval for the two-sample t-test of the previous question. Make sure you look at the alternative hypothesis before computing this interval.

we have given mean difference between men and women() = 2.2;

standard error of mean difference(SE)= 0.8;

nm = 61, n w = 61.

Ho: u men = u women

Ha: u men > u women

a ) t = () / SE = 2.2/0.8 = 2.75

t at 0.05 with 120 df (one tailed ) = 1.657

since t calculated >1.657 so we reject Ho

b ) t at 0.05 with 120 df (two tailed ) = 1.98 ( for constructing Confidence interval)

95%CI = () +/- t*SE = 2.2 +/- 1.98*0.8 = 2.2+/-1.584= (0.616,3.784)

since confidence interval do not contain 0 so we reject Ho

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