The top-selling Red and Voss tire is rated 70000 miles, which means nothing. In fact, the distance the tires can run until wear-out is a normally distributed random variable with a mean of 83000 miles and a standard deviation of 5000 miles.
A. What is the probability that the tire wears out before 70000 miles? Probability =
B. What is the probability that a tire lasts more than 91000 miles? Probability =
Solution :
Given that ,
mean = = 83000
standard deviation = = 5000
A.
P(x < 70000) = P[(x - ) / < (70000 - 83000) /5000 ]
= P(z < -2.6)
= 0.0047
Probability = 0.0047
B.
P(x > 91000) = 1 - P(x < 91000)
= 1 - P[(x - ) / < (91000 - 83000) / 5000]
= 1 - P(z < 1.6)
= 1 - 0.9452
= 0.0548
Probability = 0.0548
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