A KruskalWallis test is conducted on and experiment that was testing three different levels of a fertilizer on the growth of the same variety of tomatoes. Site 1 received no fertilizer, Site 2 received low levels of fertilizer, Site 3 received high levels of fertilizer. All sites were treated identically in terms of the amount they are watered, time of planting, etc. A random sample of 9 mature tomatoes is selected from each site. The weights are recorded.
The output is given below. At a significance level of 0.15, what is your decision and interpretation?
KruskalWallis Test: Weight versus Fertilizer Level
Descriptive Statistics
Fertilizer 
N 
Median 
Mean Rank 
ZValue 
HIGH 
9 
5 
13.5 
0.23 
LOW 
9 
7 
17.6 
1.67 
NO 
9 
5 
10.9 
1.44 
Overall 
27 
14.0 
Test
Null hypothesis 
H₀: All medians are equal 
Alternative hypothesis 
H₁: At least one median is different 
Method 
DF 
HValue 
PValue 
Not adjusted for ties 
2 
3.28 
0.194 
Adjusted for ties 
2 
3.41 
0.182 
Group of answer choices
Fail to Reject Ho, because there is enough evidence to say the levels of fertilizers do matter.
Fail to Reject Ho, because there is not enough evidence to say the level of fertilizer matters.
Fail to Reject Ho, there is enough evidence to say that the level of fertilizer matters.
Fail to Reject Ho, there is not enough evidence to say the level of fertilizer matters.
Answer :
A KruskalWallis test :
Hypothesis :
Null hypothesis
H₀: All medians are equal.
Alternative hypothesis
H₁: At least one median is different.
Analysis :
DF 
HValue 
PValue 

Not adjusted for ties 
2 
3.28 
0.194 
Adjusted for ties 
2 
3.41 
0.182 
Interpretation:
Here test statistic=H are10.432 and 3.41
and
pvalues > level of significance ( 0.15 ), we accept H0 at 0.15 level of significance.
That is , Fail to Reject Ho, there is enough evidence to say that the level of fertilizer matters.
Result:
The independent variables on dependent variable represent population with equal medians.
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