Question

In a test of the effectiveness of garlic for lowering​ cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes​ (before minus​ after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 0.4 and a standard deviation of 15.7. Use a 0.10 significance level to test the claim that with garlic​ treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic​ treatment? Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

Answer 1

n=81, = 0.4, Sd=15.7, = 0.10

null and alternative​ hypotheses are as follows

Ho: = 0

Ha: > 0

formula for test statistics is

t = 0.2293

Test statistics = 0.23

calculate p-value for right tailed test with df= n-1 = 80

using t able we get p-value as

P-Value= 0.4096

since ( P-Value= 0.4096 ) > ( = 0.10 )

Hence,

Failed to reject the null hypothesis (Ho).

Conclusion:

Therefore there is not enough sufficient evidence to conclude that garlic is effectie in lowering​ cholesterol.