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For a population that is left skewed with a mean of 24and a standard deviation equal...

For a population that is left skewed with a mean of 24and a standard deviation equal to 18​,determine the probability of observing a sample mean of 23or more from a sample of size 36.

Math   Statistics-And-Probability   
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Answer #1

µ = 24

sd = 18

n = 36

                         

                          = P(Z > -0.33)

                          = 1 - P(Z < -0.33)

                          = 1 - 0.3707

                          = 0.6293

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