Question

A random sample of 235 females and 240 males is obtained for a clinical trial. Construct...

A random sample of 235 females and 240 males is obtained for a clinical trial. Construct a 95% confidence interval to estimate the proportion of females in all such samples.

Express your answer to four decimal places.

Homework Answers

Answer #1

Sample proportion of females = 235 / (235 + 240) = 0.495

95% confidence interval for p is

- Z/2 * sqrt [ ( 1 - ) / n) ] < p < + Z/2 * sqrt [ ( 1 - ) / n) ]

0.495 - 1.96 * sqrt( 0.495 * 0.505 / 475) < p < 0.495 + 1.96 * sqrt( 0.495 * 0.505 / 475)

0.4500 < p < 0.5400

95% CI is ( 0.4500 , 0.5400)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The blood center is interested in determining which gender - males or females - is more...
The blood center is interested in determining which gender - males or females - is more likely to respond to a call to give blood. Random, independent samples of 63 females and 99 males were each asked if they would be willing to give blood when called by a local hospital. Suppose 33 of the females and 50 of the males responded that they were. Find the margin of error for a 90% confidence interval that would be used to...
1. The blood center is interested in determining which gender - males or females - is...
1. The blood center is interested in determining which gender - males or females - is more likely to respond to a call to give blood. Random, independent samples of 68 females and 87 males were each asked if they would be willing to give blood when called by a local hospital. Suppose 32 of the females and 44 of the males responded that they were. Find the margin of error for a 90% confidence interval that would be used...
In random samples of 97 females and 500 males, 19 of the females and 100 of...
In random samples of 97 females and 500 males, 19 of the females and 100 of the males said they earn more than $80,000 per year. Find an 80% confidence interval for the difference between the proportions of females and males who earn more than $80,000 per year.
In random samples of 425 females and 190 males, 80 of the females and 38 of...
In random samples of 425 females and 190 males, 80 of the females and 38 of the males said they earn more than $85,000 per year. Find a 98% confidence interval for the difference between the proportions of females and males who earn more than $85,000 per year.
In a random sample of 678 adult males 20 to 34 years of age, it was...
In a random sample of 678 adult males 20 to 34 years of age, it was determined that 58 of them have hypertension(high blood pressure). a) what conditions must be checked in order to calculate a 96% confidence interval? b) Construct a 96% confidence for the proportion of adult males 20 to 34 years of age who have hypertension. Round the endpoints to 3 decimal places. c) If we wish to conduct our own study to determine the proportion of...
In a clinical trial of a certain​ drug, 28 subjects experience headaches among the 234 subjects...
In a clinical trial of a certain​ drug, 28 subjects experience headaches among the 234 subjects treated with the drug. Construct a 99​% ​(Wald) confidence interval estimate for the proportion of treated subjects who experience​ headaches, completing parts​ (a) through​ (d) below. a. Find the best point estimate of the population proportion. __ ​(Type an integer or a decimal rounded to three decimal places as​ needed.) b. Identify the value of the margin of error E. __ ​(Type an integer...
In a random sample of 68 professional actors, it was found that 43 were extroverts. (a)...
In a random sample of 68 professional actors, it was found that 43 were extroverts. (a) Let p represent the proportion of all actors who are extroverts. Find a point estimate for p. (Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (Round your answers to two decimal places.) lower limit     upper limit     C.For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding....
A simple random sample of 400 individuals provides 128 Yes responses. (a) What is the point...
A simple random sample of 400 individuals provides 128 Yes responses. (a) What is the point estimate of the proportion of the population that would provide Yes responses? (b) What is your estimate of the standard error of the proportion, σp? (Round your answer to four decimal places.) (c) Compute the 95% confidence interval for the population proportion. (Round your answers to four decimal places.)
1,) Construct a 90% confidence interval for the population proportion if an obtained sample of size...
1,) Construct a 90% confidence interval for the population proportion if an obtained sample of size n = 150 has x = 30 2.) Construct a 95% confidence interval for the population mean if an obtained sample of size n = 35 has a sample mean of 18.4 with a sample standard deviation of 4.5.
A clinical trial tests a method designed to increase the probability of conceiving a girl. In...
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 480 babies were born, and 264 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective? < p < (Round to three decimal places as needed.) Does the method appear to be effective? Yes, the proportion of girls is significantly...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT