The manager of a grocery store has taken a random sample of 196 customers. The average length of time it took these 196 customers to check out was 3 minutes. It is known that the standard deviation of the population of checkout times is 1 minute. The margin of error is 0.140. Find the 95% confidence interval for the true average checkout time (in minutes).
A. 1 to 5
B. 2.86 to 3.14
C. 2.883 to 3.117
D. 2.990 to 3.010
n = 196 sample size
minute sample mean
s =1 minute sample standard deviations
level of significance
Margin of error = 0.140
The 95% confidence interval for the true average is
. Here n >30
from Z table
( 2.86 , 3.14)
The 95 % confidence interval for the true average check out time in minutes is (2.86 to 3.14)
Option B is correct
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