Question

The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a variety of information on each county in America. In the third quarter of 2016, the QCEW reported the total taxable earnings, in millions, of all wage earners in all 3222 counties in America. Suppose that James is an economist who collects a simple random sample of the total taxable earnings of workers in 50 American counties during the third quarter of 2016. According to the QCEW, the true population mean and standard deviation of taxable earnings, in millions of dollars, by county are μ = 28.29 and σ = 33.493 , respectively. Let X be the total taxable earnings, in millions, of all wage earners in a county. The mean total taxable earnings of all wage earners in a county across all the counties in James' sample is ¯¯¯ x . Use the central limit theorem (CLT) to determine the probability P that the mean taxable wages in James' sample of 50 counties will be less than $ 26 million. Report your answer to four decimal places.

2.Use the CLT again to determine the probability that the mean taxable wages in James' sample of 50 counties will be greater than $24 million. Report your answer to four decimal places.

Homework Answers

Answer #1

a)

Here, μ = 28.29, σ = 4.7366 and x = 26. We need to compute P(X <= 26). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z = (26 - 28.29)/4.7366 = -0.48

Therefore,
P(X <= 26) = P(z <= (26 - 28.29)/4.7366)
= P(z <= -0.48)
= 0.3156


b)

Here, μ = 28.29, σ = 4.7366 and x = 24. We need to compute P(X >= 24). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z = (24 - 28.29)/4.7366 = -0.91

Therefore,
P(X >= 24) = P(z <= (24 - 28.29)/4.7366)
= P(z >= -0.91)
= 1 - 0.1814 = 0.8186

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