Question

**Basic Stat Psychology
It covers z tests and inferential statistics**

**Conduct a z-test
PLEASE SHOW WORK SO I CAN UNDERSTAND**

One-hundred test scores were recently obtained from a local high school to compare to the national average. The mean verbal SAT score for this sample was 445. Compare this sample to the population of SAT verbal test scores (SAT Verbal Test ? = 430 and ? = 120). Alpha=.05

**A.** Should a one-tailed or two-tailed test be
used?

**B.** State your null hypothesis

**C.** State your alternative hypothesis

**D.** What is the z-obtained?

**E.** What is the p value?

**F.** Did you reject or fail to reject the null
hypothesis?

**G.** What can you conclude on the basis of the
results?

**(Make sure to show your work!)
&&& IT ELIGIBLE WRITING. THANK YOU!**

Answer #1

A. In this case, a two tailed hypothesis should be used because the direction of the difference cannot be predicted beforehand.

B. The null hypothesis: There is no significant difference between the SAT scores of the local high school and the national average.

C. The alternative hypothesis: There is a significant difference between the SAT scores of the local high school and the national average.

D. The basic z score formula for a sample is:

**z = (x – ?) / ?**

We have a local school test score of 445. The population has a mean
(?) of 430 and a standard deviation (?) of 120. Assuming a normal
distribution, the z score would be:

z = (x – ?) / ?

= 430 – 445 / 120 = 0.125.

Please post the other questions separately as we are supposed to answer just one question or four sub parts of a question.

One-hundred test scores were recently obtained from a local
high school to compare to the national average. The mean verbal SAT
score for this sample was440. Compare this sample to the population
of SAT verbal test scores (SAT Verbal Test μ = 430 and σ =
120).
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