Question

A 50.0-kg grindstone is a solid disk 0.510 m in diameter. You press an ax down...

A 50.0-kg grindstone is a solid disk 0.510 m in diameter. You press an ax down on the rim with a normal force of 180 N . The coefficient of kinetic friction between the blade and the stone is 0.60, and there is a constant friction torque of 6.50N?m between the axle of the stone and its bearings.

A)How much force must be applied tangentially at the end of a crank handle 0.500 m long to bring the stone from rest to 120 rev/min in 8.00 s ?

B) After the grindstone attains an angular speed of 120 rev/min, what tangential force at the end of the handle is needed to maintain a constant angular speed of 120 rev/min?

C) How much time does it take the grindstone to come from 120 rev/min to rest if it is acted on by the axle friction alone?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 65.0-kg grindstone is a solid disk 0.550m in diameter. You press an ax down on...
A 65.0-kg grindstone is a solid disk 0.550m in diameter. You press an ax down on the rim with a normal force of 150N (Figure 1) . The coefficient of kinetic friction between the blade and the stone is 0.60, and there is a constant friction torque of 6.50N?m between the axle of the stone and its bearings. Part A How much force must be applied tangentially at the end of a crank handle 0.500 m long to bring the...
A grindstone of mass m = 50.0 kg is a solid disk 0.480 m in diameter....
A grindstone of mass m = 50.0 kg is a solid disk 0.480 m in diameter. You press an ax down on the rim with a normal force of F = 155 N The coefficient of kinetic friction between the blade and the stone is 0.50, and there is a constant friction torque of 6.5 Nm between the axle of the stone and its bearings. (a) While you are pressing the ax against the rim, how much force would your...
A grindstone in the shape of a solid disk with diameter 0.510 m and a mass...
A grindstone in the shape of a solid disk with diameter 0.510 m and a mass of m = 50.0 kg is rotating at ω = 830 rev/min . You press an ax against the rim with a normal force of F = 170 N (Figure 1) , and the grindstone comes to rest in 8.00 s . Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.
You have a grindstone (a disk) that is 91.0 kg, has a 0.370-m radius, and is...
You have a grindstone (a disk) that is 91.0 kg, has a 0.370-m radius, and is turning at 68.0 rpm, and you press a steel axe against it with a radial force of 11.0 N. (a) Assuming the kinetic coefficient of friction between steel and stone is 0.50, calculate the angular acceleration (in rad/s2) of the grindstone. (Indicate the direction with the sign of your answer.) _____rad/s2 (b) How many turns (in rev) will the stone make before coming to...
You have a horizontal grindstone (a disk) that is 86 kg, has a 0.38 m radius,...
You have a horizontal grindstone (a disk) that is 86 kg, has a 0.38 m radius, is turning at 88 rpm (in the positive direction), and you press a steel axe against the edge with a force of 18 N in the radial direction. Assuming that the kinetic coefficient of friction between steel and stone is 0.20, calculate the angular acceleration of the grindstone in rad/s2. What is the number of turns, N, that the stone will make before coming...
A potter’s wheel, a thick stone disk of radius 0.500 m and mass 100 kg, is...
A potter’s wheel, a thick stone disk of radius 0.500 m and mass 100 kg, is freely rotating at 70.0 rev/min. The potter can stop the wheel by pressing a wet rag against the rim and exerting a radially inward force of 35.0 N. If the applied force slows the wheel down with an angular acceleration of 0.875rad/s2 , calculate the torque acting on the wheel and the coefficient of kinetic friction between the wheel and the rag
A 170-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m...
A 170-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rev/s in 2.00 s? (State the magnitude of the force.)
Part A) A potter's wheel—a thick stone disk of radius 0.400 m and mass 138 kg—is...
Part A) A potter's wheel—a thick stone disk of radius 0.400 m and mass 138 kg—is freely rotating at 60.0 rev/min. The potter can stop the wheel in 5.00 s by pressing a wet rag against the rim and exerting a radially inward force of 58.9N. Find the effective coefficient of kinetic friction between the wheel and rag. Part B) The net work done in accelerating a solid cylindrical wheel from rest to an angular speed of 50rev/ min is...
10.4-5-6) A) A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with...
10.4-5-6) A) A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 2.10 m/s2. The car makes it one quarter of the way around the circle before it skids off the track. From these data, determine the coefficient of static friction between the car and track. ________ (Hint: You are not given a value of the radius of the track. Think through the problem using the symbol R for this value and...
A uniform-density wheel of mass 8 kg and radius 0.42 m rotates on a low-friction axle....
A uniform-density wheel of mass 8 kg and radius 0.42 m rotates on a low-friction axle. Starting from rest, a string wrapped around the edge exerts a constant force of 14 N for 0.84 s. (a) What is the final angular speed? (a) ωf = radians/s (b) What was the average angular speed? ωaverage = radians/s (c) Through how big an angle did the wheel turn? θ = radians (d) How much string came off the wheel? d = m
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT