Question

Two cars start from rest at a red stop light. When the light turns green, both...

Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates uniformly at a rate of 5.7 m/s2 for 3.1 seconds. It then continues at a constant speed for 8.4 seconds, before applying the brakes such that the car’s speed decreases uniformly coming to rest 202 meters from where it started. The yellow car accelerates uniformly for the entire distance, finally catching the blue car just as the blue car comes to a stop.

4)

What is the acceleration of the blue car once the brakes are applied?

m/s2

5)

What is the total time the blue car is moving?

6)

What is the acceleration of the yellow car?

m/s2

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Homework Answers

Answer #1

We need to find distance travelled by blue car before brakes are applied

v2 = u2 + 2ad

d = (17.67)2 / 2*5.7

d = 27.3885

d = 8.4*17.67 = 148.428 m

Total distance = 148.428 + 27.3885 = 175.8165 m

4) Now distance travelled once the brake is applied

d = 202 - 175.8165 = 26.1835 m

so, a = -(17.67)2 / 2*26.1835

a = - 5.9623 m/s2

5) time taken for full stop after brake is applied t = 17.67 / 5.9623 = 2.9636 sec

Total time blue car is moving , T = 3.1 + 8.4 + 2.9636 = 14.4636 seconds

6) a = 2*202 / 14.46362

a = 1.9312 m/s2

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