Question

. An 80 kg baseball player goes into his slide when he is 6.00meters from second base. He comes to rest just as he touches the bag 1.50 seconds later

Assume that his acceleration is uniform.

a) Find this acceleration

b) Find his speed when he begins the slide

c) Find the magnitude of the frictional force acting on him during his slide.

d) Find the work done by this frictional force

Answer 1

Here

d = 6 m

t = 1.50 s

m = 80 Kg

a) let the acceleration is a

d = 0.50 * a * t^2

6 = 0.50 * a * 1.50^2

a = 5.33 m/s^2

the acceleration is 5.33 m/s^2

b)

speed when he begins = a * t

speed when he begins = 5.33 * 1.50

speed when he begins = 8 m/s

c)

magnitude of frictional force = m * a

magnitude of frictional force = 80 * 5.33

magnitude of frictional force = 426 N

D)

Work done by frictional force = - Force * distance

Work done by frictional force = - 426 * 6

Work done by frictional force = - 2560 J