Question

What is the slope of an F versus (1/n^2) graph?

The equation I'm supposed to determine it from is F= (4*density*f^2*L^2)*(1/n^2)

How would I also determine the slope from the graph given

n=1 F= 2.8

n= 2 F = 1.03

n= 3 F= .873

n=4 F=.469

n=5 F= .237

Answer 1

The given expression is
   
where,
  
So, the graph is a straight line passing through the origin.
And the slope cann be written in a more compact form
   
  1)
  for n = 1, F = 2.8, we have
   
2)
   for n = 2, F = 1.03, we have
   
3)
  for n = 3, F = 0.873, we have
   
4)
  for n = 4, F = 0.469, we have
   
5)
for n = 5, F = 0.237, we have