Question

How much energy is required to change a 40 g ice cube from ice at -10 oC to steam at 110 oC?

cwater=4186 J kg-1 oC-1

cice=2090 J kg-1 oC-1

cvapor=2010 J kg-1 oC-1

Lf=3.3x105 J kg-1

Lv=2.26x106 J kg-1

Answer #1

Useful information:

heat of fusion of water = 334 J/g

heat of vaporization of water = 2257 J/g

specific heat of ice = 2.09 J/g·°C

specific heat of water = 4.18 J/g·°C

specific heat of steam = 2.09 J/g·°C

**Step 1:** Heat required to raise the temperature
of ice from -10 °C to 0 °C Use the formula

q1 = mcΔT = 40* 2.09* ( 0--10) =836 J

**Step 2:** Heat required to convert 0 °C ice to 0
°C water

q2 = m·ΔH = 40 *334 = 13360 J

**Step 3:** Heat required to raise the temperature
of 0 °C water to 100 °C water

q3 = mcΔT = 40 *4.18* ( 100-0) = 16720J

**Step 4:** Heat required to convert 100 °C water
to 100 °C steam

q4 = m·ΔH_{v} = 40*2275 = 91000 J

**Step 5:** Heat required to convert 100 °C steam
to 110 °C steam

q5 = mcΔT = 40*2.09*( 110-100) = 836 J

**Step 6:** Find total heat energy

Heat_{Total} = Heat_{Step 1} + Heat_{Step
2} + Heat_{Step 3} + Heat_{Step 4} +
Heat_{Step 5}

= 836+13360+16720+91000+836

**=122752 J**

17. How much heat is required to change the temperature of 50 g
of ice cube initially at - 30 0C to steam at 160
0C? (Express your answer in J){ specific heat of ice is
2090 J/kg 0C, that of water is 4186 J/kg 0C,
that of steam is 2010 J/kg 0C; Lf = 3.33 X 10 J/kg, Lv =
2.26 X 10 J/kg.}

How much energy is required to change a 23 g ice cube from ice
at − 12 ◦ C to steam at 101 ◦ C? The specific heat of ice is 2090 J
/ kg · ◦ C and of water 4186 J / kg · ◦ C. The latent heat of
fusion of water is 3 . 33 × 10^5 J / kg, its latent heat of
vaporization is 2 . 26 × 10^6 J / kg, and the...

How much energy is required to change a 34 g ice cube from ice
at −10◦C to steam at 119◦C? The specific heat of ice is 2090 J/kg ·
◦ C, the specific heat of water is 4186 J/kg · ◦ C, the specific
heat of stream is 2010 J/kg · ◦ C, the heat of fusion is 3.33 × 105
J/kg, and the heat of vaporization is 2.26 × 106 J/kg. Answer in
units of J

1. How much heat is required to change a 32.3 g ice
cube from ice at -10.6°C to water at 47°C? (if necessary, use
cice=2090 J/kg°C and csteam= 2010 J/kg°C)
2. How much heat is required to change a 32.3 g ice
cube from ice at -10.6°C to steam at 111°C?

Part A:
How much heat is required to change a 37.9 g ice cube from ice
at -14.1°C to water at 30°C? (if necessary, use cice=2090 J/kg°C
and csteam= 2010 J/kg°C)
Part B:
How much heat is required to change a 37.9 g ice cube from ice
at -14.1°C to steam at 112°C?

How much heat is required to change a 48.4 g ice cube from ice
at -11.5°C to water at 72°C? (if necessary, use cice=2090 J/kg°C
and csteam= 2010 J/kg°C)
How much heat is required to change a 48.4 g ice cube from ice
at -11.5°C to steam at 116°C?

How much energy is required to change a 35 g
ice cube from ice at ?7
?C to steam at 108?C?
The specific heat of ice is 2090 J/kg

How much energy is required to change a 40-g ice cube from ice
at -10 Celsius to steam at 110 Celsius?

A) How much heat is required to change a 44.4 g ice cube from
ice at -13.2 degrees Celsius to water at 80 degrees Celsius? (If
necessary, use c of ice= 2090 J/kg degrees Celsius and c of steam=
2010 J/ kg degrees Celsius) B) How much heat is required to change
a 44.4 g ice cube from ice at -13.2 degrees Celsius to steam at 117
degrees Celsius?

How much energy in Joules is required to change a 30-g ice cube
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