Question

Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.125 kg apple toward astronaut 2 with a speed of vi,1 = 1.08 m/s . The 0.170 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.25 m/s . Unfortunately, the fruits collide, sending the orange off with a speed of 0.952 m/s in the negative y direction.

Part B

? =

  ? counterclockwise from the positive x axis

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Answer 1

Here we have to find apple's direction

Let's assume Apple is going from right to left while orange from left to right
Let us say that momentum of apple at an angle () to the x-axis is m*v

x-direction

0.125*v cos = (0.170*1.25) -(0.125*1.08)

0.125*v cos = 0.077-------------------------(1)

y direction component

0.125*v sin = (0.170*0.952)

0.125*v sin = 0.161--------------(2)

Dividing eq (2) by (1)

0.125 sin /0.125 cos = 0.161/0.077

Tan = 2.077

= Tan ^-1 (2.077)

= 64.2 degree