Question

A physics student places an object 6.0 cm from a converging lens of focal length 9.0 cm. What is the magnitude of the magnification of the image produced? 1. |M| = 3.6 2. |M| = 0.6 3. |M| = 1.5 4. |M| = 2.0 5. |M| = 3.0

Answer 1

Given that object is placed 6.0 cm from a converging lens, So

u = object distance = 6.0 cm

v = image distance = ?

f = focal length of converging lens = 9.0 cm

So, Using lens equation:

1/f = 1/u + 1/v

1/v = 1/f - 1/u

v = u*f/(u - f)

v = 6.0*9.0/(6.0 - 9.0)

v = -18.0 cm

Now magnification of image produced is given by:

M = -v/u

M = -(-18.0)/6.0

M = +3.0

Sinwe need magnitude of magnification, So

|M| = |+3.0| = 3.0

Correct option is 5.

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