Question

An interference pattern is produced by light with a wavelength 600 nm from a distant source incident on two identical parallel slits separated by a distance (between centers) of 0.500 mm .

**Part A**

If the slits are very narrow, what would be the angular position of the first-order, two-slit, interference maxima?

**Part B**

What would be the angular position of the second-order, two-slit, interference maxima in this case?

**Part C**

Let the slits have a width 0.330 mm . In terms of the intensity
*I*0 at the center of the central maximum, what is the
intensity at the angular position of *?*1?

**Part D**

What is the intensity at the angular position of
*?*2?

Answer #1

**Part A**

To determine the angular position of the interference maxima we use the following equation:

solving for ,we have

as it is for first order then m = 1

transformed d = 0.500mm to nm (d = 500000nm)

**Part b**

it is done the same as in part A but now m = 2

**Part C**

In this case d = 0.330mm.

The intensity for any is known by the following equation:

is the intensity of the waves produced if they act alone, we will take = 1.

d=0.330mm=330000nm and

**Part D**

In this case d = 0.330mm.

The intensity for any is known by the following equation:

is the intensity of the waves produced if they act alone, we will take = 1.

d=0.330mm=330000nm and

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