A movie star catches a reporter shooting pictures of
her at home. She claims the reporter was trespassing. To
prove her point, she gives as evidence the film she seized.
Her 1.75 m height is 8.25 mm high on the film, and the focal
length of the camera lens was 220 mm. How far away from
the subject was the reporter standing?
Using lens equation and Magnification
M = Magnification = hi/ho = -v/u
hi = height of image = -8.25 mm = -0.00825 m
ho = height of object = 1.75 m
u = object distance
v = image distance
So,
M = -0.00825/1.75 = -v/u
u = v*(1.75)/0.00825 = 212.12*v
Now given that
f = focal length of lens = 220 mm
So, Using lens equation
1/f = 1/u + 1/v
1/f = 1/v + 1/(212.12*v)
1/f = (1/v)*(213.12/212.12)
v = f*213.12/212.12
Using value of 'f'
v = 220*213.12/212.12 = 221.04 mm
u = 212.12*v = 212.12*221.04
u = -46887 mm
u = -46.887 m = 46.9 m
So the reporter was standing at 46.9 m from the actor.
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