Question

Ship A sails east at 3 m/s while ship B is 100 km to the northeast...

Ship A sails east at 3 m/s while ship B is 100 km to the northeast of A and heading south at 4 m/s.

a. What is the velocity of B relative to A?

b. If the velocities are maintained, what is their distance of closest approach? Use a refrence frame in which A is at rest. (hint: thisis a max/min problem)

c. If A has a radio with a 20-km range, how long can the ships communicate?

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Answer #1

PLEASE RATE THIS QUESTION...................IT WOULD BE GREAT.........LET ME KNOW IF YOU HAVE ANY DOUBT........

(a) velocity of B relative to A

v = -3i - 4j

|v| = sqrt ((3)2 + (4)2)

|v| = sqrt(25)

v = 5 m/s

direction = tan-1 (3/4)

direction = 36.869 degree (west of south)

(b) distance of closest approach

If A is at rest (not moving) then the ultimate velocity in this frame will be the velocity of B relative to A. As B is 100 km away from A, Lets's draw it to better understand. I will solve both parts B and C on a notebook as they involve little geometry.

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