Two lenses in contact: Find the equivalent power, the image location, and magnification
f1 = 5 cm f2 = -10cm d12 = 0 p1 = 20 cm
Answer: P = +10 D; q = +20 cm; m= -1
I need to know how to solve this problem
let f is resultant focal length.
we know, when two lenses are in contact
1/f = 1/f1 + 1/f2 +
1/f = 1/5 + 1/(-10)
f = 10 cm = 0.1 m
Power of the resultant lenses, P = 1/f
= 1/0.1
= 10 D <<<<<<----------------Answer
let object distance p = 20 cm
let q is the image distance.
use, 1/p + 1/q = 1/f
1/q = 1/f - 1/p
1/q = 1/10 - 1/20
q = 20 cm <<<<<<----------------Answer
magnification, m = -p/q
= -20/20
= -1 <<<<<----------------Answer
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