The radioactive isotope 198Au has a half-life of 64.8 hours. A sample containing this isotope has an initial activity at (t=0) of 1.50e-12 Bq. Calculate the number of nuclei that will decay in the time interval between t1=10 hours and t2=20 hours
Answer is 4.60e16 but I'm not sure how. Thanks and please show work
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