Question

The work done by an external force to move a -6.70 μC charge from point A to point B is 1.90×10−3 J . Part A...

The work done by an external force to move a -6.70 μC charge from point A to point B is 1.90×10−3 J .


Part A


If the charge was started from rest and had 4.90×10−4 J of kinetic energy when it reached point B, what must be the potential difference between A and B?

Express your answer with the appropriate units.

VB−VA= ?

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