An aluminum cup contains 225 g of water and a 40-g copper
stirrer, all at 27°C. A 441-g sample of silver at an initial
temperature of 85°C is placed in the water. The stirrer is used to
stir the mixture gently until it reaches its final equilibrium
temperature of 32°C. Calculate the mass of the aluminum cup.
My answer: 163.7 g
Your response is within 10% of the correct value. This may be due
to roundoff error, or you could have a mistake in your calculation.
Carry out all intermediate results to at least four-digit accuracy
to minimize roundoff error.
Let the mass od the aluminum cup is mal.
Given that
The mass of the copper stirrer mc=40 g.
The mass of the water mw=225 g.
The mass of the silver sample msi=441 g.
The temperature of the water, cup, the stirrer is T1=27oC.
The temperature of the silver Tsi=85oC.
The final temperature of the system T=32oC.
Now from the conservation of heat energy, we can say
The mass of the aluminum cup is 165.6 g.
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