A person starts to run around a square track with sides of 50 m starting in the bottom right corner and running counter-clockwise. Running at an average speed of 5 m/s, the jogger runs for 53.80 seconds. What is the difference between the magnitude of the person's average velocity and average speed in m/s? (please provide detailed explanation)
vs = average speed = 5 m/s
t = time of travel = 53.80 s
distance travelled is given as
D = vs t
D = 5 x 53.80 = 269 m
after travelling distance of 269 m , the person is at point P
hence displacement is given as
AP = sqrt(AB2 + BP2)
AP = sqrt(502 + 192)
AP = 53.5 m
average velocity is given as
V = (AP)/t = 53.5/53.8 = 0.994 m/s
difference in magnitude of average speed and average velocity is given as
difference = average speed - average velocity = 5 - 0.994 = 4.006 m /s
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